Base | Representation |
---|---|
bin | 11110011101111101010101… |
… | …100100100010111000000100 |
3 | 122120110021201210002102210001 |
4 | 132131331111210202320010 |
5 | 120030424221244430200 |
6 | 1152554445550411044 |
7 | 40140121620303445 |
oct | 3635752544427004 |
9 | 576407653072701 |
10 | 134000120311300 |
11 | 3977314a5a3521 |
12 | 13042155200a84 |
13 | 59a0207286429 |
14 | 25138d74992cc |
15 | 10759b5dbb76a |
hex | 79df55922e04 |
134000120311300 has 72 divisors (see below), whose sum is σ = 290981387249280. Its totient is φ = 53562981532800.
The previous prime is 134000120311289. The next prime is 134000120311303. The reversal of 134000120311300 is 3113021000431.
It is not an unprimeable number, because it can be changed into a prime (134000120311303) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1660699557 + ... + 1660780243.
It is an arithmetic number, because the mean of its divisors is an integer number (4041408156240).
Almost surely, 2134000120311300 is an apocalyptic number.
134000120311300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134000120311300 is an abundant number, since it is smaller than the sum of its proper divisors (156981266937980).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134000120311300 is a wasteful number, since it uses less digits than its factorization.
134000120311300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91981 (or 91974 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 134000120311300 its reverse (3113021000431), we get a palindrome (137113141311731).
The spelling of 134000120311300 in words is "one hundred thirty-four trillion, one hundred twenty million, three hundred eleven thousand, three hundred".
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