Base | Representation |
---|---|
bin | 111110011001100001… |
… | …0101001110111110111 |
3 | 110210212201020120000111 |
4 | 1330303002221313313 |
5 | 4143413040214431 |
6 | 141320415523451 |
7 | 12452436632566 |
oct | 1746302516767 |
9 | 423781216014 |
10 | 134000319991 |
11 | 5191376180a |
12 | 21b78529587 |
13 | c8368a8a95 |
14 | 66b28a3bdd |
15 | 374414d7b1 |
hex | 1f330a9df7 |
134000319991 has 2 divisors, whose sum is σ = 134000319992. Its totient is φ = 134000319990.
The previous prime is 134000319949. The next prime is 134000320009. The reversal of 134000319991 is 199913000431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134000319991 - 27 = 134000319863 is a prime.
It is a super-3 number, since 3×1340003199913 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134000319491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67000159995 + 67000159996.
It is an arithmetic number, because the mean of its divisors is an integer number (67000159996).
Almost surely, 2134000319991 is an apocalyptic number.
134000319991 is a deficient number, since it is larger than the sum of its proper divisors (1).
134000319991 is an equidigital number, since it uses as much as digits as its factorization.
134000319991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 40.
The spelling of 134000319991 in words is "one hundred thirty-four billion, three hundred nineteen thousand, nine hundred ninety-one".
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