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1340103400151 = 10132417954713
BaseRepresentation
bin10011100000000100011…
…000110001101011010111
311202010001002222021001212
4103200010120301223113
5133424012432301101
62503345054412035
7165551003645345
oct23400430615327
94663032867055
101340103400151
114773754842aa
12197879b0101b
13994a9711009
1448c0b790995
1524cd4a341bb
hex13804631ad7

1340103400151 has 8 divisors (see below), whose sum is σ = 1341506303280. Its totient is φ = 1338700656832.

The previous prime is 1340103400133. The next prime is 1340103400183. The reversal of 1340103400151 is 1510043010431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340103400151 - 214 = 1340103383767 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340103402151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24465971 + ... + 24520683.

It is an arithmetic number, because the mean of its divisors is an integer number (167688287910).

Almost surely, 21340103400151 is an apocalyptic number.

1340103400151 is a deficient number, since it is larger than the sum of its proper divisors (1402903129).

1340103400151 is a wasteful number, since it uses less digits than its factorization.

1340103400151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79905.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 1340103400151 its reverse (1510043010431), we get a palindrome (2850146410582).

The spelling of 1340103400151 in words is "one trillion, three hundred forty billion, one hundred three million, four hundred thousand, one hundred fifty-one".

Divisors: 1 1013 24179 54713 24493327 55424269 1322905627 1340103400151