13401044351 has 2 divisors, whose sum is σ = 13401044352. Its totient is φ = 13401044350.

The previous prime is 13401044347. The next prime is 13401044353. The reversal of 13401044351 is 15344010431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13401044351 - 2² = 13401044347 is a prime.

It is a super-2 number, since 2×13401044351² (a number of 21 digits) contains 22 as substring.

Together with 13401044353, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13401044351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401044353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700522175 + 6700522176.

It is an arithmetic number, because the mean of its divisors is an integer number (6700522176).

Almost surely, 2^13401044351 is an apocalyptic number.

13401044351 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401044351 is an equidigital number, since it uses as much as digits as its factorization.

13401044351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 13401044351 its reverse (15344010431), we get a palindrome (28745054782).

The spelling of 13401044351 in words is "thirteen billion, four hundred one million, forty-four thousand, three hundred fifty-one".