13401143141 has 2 divisors, whose sum is σ = 13401143142. Its totient is φ = 13401143140.

The previous prime is 13401143083. The next prime is 13401143143. The reversal of 13401143141 is 14134110431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9614586916 + 3786556225 = 98054^2 + 61535^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401143141 - 2²⁶ = 13334034277 is a prime.

Together with 13401143143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401143143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700571570 + 6700571571.

It is an arithmetic number, because the mean of its divisors is an integer number (6700571571).

Almost surely, 2^13401143141 is an apocalyptic number.

It is an amenable number.

13401143141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401143141 is an equidigital number, since it uses as much as digits as its factorization.

13401143141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13401143141 its reverse (14134110431), we get a palindrome (27535253572).

The spelling of 13401143141 in words is "thirteen billion, four hundred one million, one hundred forty-three thousand, one hundred forty-one".