1340117 has 4 divisors (see below), whose sum is σ = 1344000. Its totient is φ = 1336236.

The previous prime is 1340113. The next prime is 1340149. The reversal of 1340117 is 7110431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 7110431 = 601 ⋅11831.

It is a cyclic number.

It is not a de Polignac number, because 1340117 - 2² = 1340113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340095 and 1340104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1367 + ... + 2132.

It is an arithmetic number, because the mean of its divisors is an integer number (336000).

2^1340117 is an apocalyptic number.

It is an amenable number.

1340117 is a deficient number, since it is larger than the sum of its proper divisors (3883).

1340117 is an equidigital number, since it uses as much as digits as its factorization.

1340117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3882.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 1340117 is about 1157.6342254788. The cubic root of 1340117 is about 110.2505857439.

Adding to 1340117 its reverse (7110431), we get a palindrome (8450548).

The spelling of 1340117 in words is "one million, three hundred forty thousand, one hundred seventeen".