134012113330434 has 16 divisors (see below), whose sum is σ = 273726869781888. Its totient is φ = 43720263923312.

The previous prime is 134012113330423. The next prime is 134012113330477. The reversal of 134012113330434 is 434033311210431.

It is a junction number, because it is equal to n+sod(n) for n = 134012113330395 and 134012113330404.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 237610129737 + ... + 237610130300.

It is an arithmetic number, because the mean of its divisors is an integer number (17107929361368).

Almost surely, 2^{134012113330434} is an apocalyptic number.

134012113330434 is an abundant number, since it is smaller than the sum of its proper divisors (139714756451454).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134012113330434 is a wasteful number, since it uses less digits than its factorization.

134012113330434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 475220260089.

The product of its (nonzero) digits is 31104, while the sum is 33.

Adding to 134012113330434 its reverse (434033311210431), we get a palindrome (568045424540865).

The spelling of 134012113330434 in words is "one hundred thirty-four trillion, twelve billion, one hundred thirteen million, three hundred thirty thousand, four hundred thirty-four".