134012113330433 has 16 divisors (see below), whose sum is σ = 145646323228560. Its totient is φ = 122567296870656.

The previous prime is 134012113330423. The next prime is 134012113330477. The reversal of 134012113330433 is 334033311210431.

It is a happy number.

It can be written as a sum of positive squares in 8 ways, for example, as 531801187009 + 133480312143424 = 729247^2 + 11553368^2 .

It is a cyclic number.

It is not a de Polignac number, because 134012113330433 - 2¹⁸ = 134012113068289 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134012113330433.

It is not an unprimeable number, because it can be changed into a prime (134012113330423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 149126291 + ... + 150022247.

It is an arithmetic number, because the mean of its divisors is an integer number (9102895201785).

Almost surely, 2^{134012113330433} is an apocalyptic number.

134012113330433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

134012113330433 is a deficient number, since it is larger than the sum of its proper divisors (11634209898127).

134012113330433 is a wasteful number, since it uses less digits than its factorization.

134012113330433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1001636.

The product of its (nonzero) digits is 23328, while the sum is 32.

Adding to 134012113330433 its reverse (334033311210431), we get a palindrome (468045424540864).

The spelling of 134012113330433 in words is "one hundred thirty-four trillion, twelve billion, one hundred thirteen million, three hundred thirty thousand, four hundred thirty-three".