13401212121 has 24 divisors (see below), whose sum is σ = 21371497056. Its totient is φ = 8024087040.

The previous prime is 13401212119. The next prime is 13401212141. The reversal of 13401212121 is 12121210431.

13401212121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13401212121 - 2¹ = 13401212119 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13401212094 and 13401212103.

It is not an unprimeable number, because it can be changed into a prime (13401212141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 807240 + ... + 823673.

It is an arithmetic number, because the mean of its divisors is an integer number (890479044).

Almost surely, 2^13401212121 is an apocalyptic number.

13401212121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13401212121 is a deficient number, since it is larger than the sum of its proper divisors (7970284935).

13401212121 is a wasteful number, since it uses less digits than its factorization.

13401212121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1631013 (or 1631010 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 13401212121 its reverse (12121210431), we get a palindrome (25522422552).

It can be divided in two parts, 13401 and 212121, that added together give a palindrome (225522).

The spelling of 13401212121 in words is "thirteen billion, four hundred one million, two hundred twelve thousand, one hundred twenty-one".