Base | Representation |
---|---|
bin | 111110011001111000… |
… | …1001111000100111101 |
3 | 110210220120012221101021 |
4 | 1330303301033010331 |
5 | 4143424201443010 |
6 | 141321533344141 |
7 | 12452645501323 |
oct | 1746361170475 |
9 | 423816187337 |
10 | 134012531005 |
11 | 5191a642061 |
12 | 21b80638051 |
13 | c839292b32 |
14 | 66b4361d13 |
15 | 37452618da |
hex | 1f33c4f13d |
134012531005 has 4 divisors (see below), whose sum is σ = 160815037212. Its totient is φ = 107210024800.
The previous prime is 134012530991. The next prime is 134012531039. The reversal of 134012531005 is 500135210431.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 500135210431 = 29 ⋅17246041739.
It can be written as a sum of positive squares in 2 ways, for example, as 57683550276 + 76328980729 = 240174^2 + 276277^2 .
It is not a de Polignac number, because 134012531005 - 215 = 134012498237 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13401253096 + ... + 13401253105.
It is an arithmetic number, because the mean of its divisors is an integer number (40203759303).
Almost surely, 2134012531005 is an apocalyptic number.
It is an amenable number.
134012531005 is a deficient number, since it is larger than the sum of its proper divisors (26802506207).
134012531005 is an equidigital number, since it uses as much as digits as its factorization.
134012531005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26802506206.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 134012531005 its reverse (500135210431), we get a palindrome (634147741436).
The spelling of 134012531005 in words is "one hundred thirty-four billion, twelve million, five hundred thirty-one thousand, five".
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