1340131111 has 4 divisors (see below), whose sum is σ = 1461961224. Its totient is φ = 1218301000.

The previous prime is 1340131099. The next prime is 1340131127. The reversal of 1340131111 is 1111310431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340131111 - 2¹⁵ = 1340098343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340131511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60915040 + ... + 60915061.

It is an arithmetic number, because the mean of its divisors is an integer number (365490306).

Almost surely, 2^1340131111 is an apocalyptic number.

1340131111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1340131111 is a deficient number, since it is larger than the sum of its proper divisors (121830113).

1340131111 is a wasteful number, since it uses less digits than its factorization.

1340131111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121830112.

The product of its (nonzero) digits is 36, while the sum is 16.

The square root of 1340131111 is about 36607.8012314315. The cubic root of 1340131111 is about 1102.5097271026.

Adding to 1340131111 its reverse (1111310431), we get a palindrome (2451441542).

The spelling of 1340131111 in words is "one billion, three hundred forty million, one hundred thirty-one thousand, one hundred eleven".