Base | Representation |
---|---|
bin | 11000111101100100… |
… | …10010010001111010 |
3 | 1021120222002200100112 |
4 | 30132302102101322 |
5 | 204421224303232 |
6 | 10053450304322 |
7 | 653046011213 |
oct | 143662222172 |
9 | 37528080315 |
10 | 13401400442 |
11 | 5757817561 |
12 | 27201280a2 |
13 | 13575b3861 |
14 | 911bb640a |
15 | 5367e04b2 |
hex | 31ec9247a |
13401400442 has 4 divisors (see below), whose sum is σ = 20102100666. Its totient is φ = 6700700220.
The previous prime is 13401400421. The next prime is 13401400567. The reversal of 13401400442 is 24400410431.
It is a happy number.
13401400442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9570904561 + 3830495881 = 97831^2 + 61891^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350350109 + ... + 3350350112.
Almost surely, 213401400442 is an apocalyptic number.
13401400442 is a deficient number, since it is larger than the sum of its proper divisors (6700700224).
13401400442 is an equidigital number, since it uses as much as digits as its factorization.
13401400442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6700700223.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 13401400442 its reverse (24400410431), we get a palindrome (37801810873).
The spelling of 13401400442 in words is "thirteen billion, four hundred one million, four hundred thousand, four hundred forty-two".
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