Base | Representation |
---|---|
bin | 11110011110001010011000… |
… | …001010011100001010100110 |
3 | 122120111121212121120110002100 |
4 | 132132022120022130022212 |
5 | 120031141410321142210 |
6 | 1153005123220552530 |
7 | 40141125612412215 |
oct | 3636123012341246 |
9 | 576447777513070 |
10 | 134014122443430 |
11 | 39779085418649 |
12 | 13044a02552746 |
13 | 59a1629160908 |
14 | 2514464d6907c |
15 | 10760352c15c0 |
hex | 79e29829c2a6 |
134014122443430 has 48 divisors (see below), whose sum is σ = 348464350890864. Its totient is φ = 35734265211840.
The previous prime is 134014122443413. The next prime is 134014122443459. The reversal of 134014122443430 is 34344221410431.
134014122443430 is a `hidden beast` number, since 1 + 3 + 40 + 14 + 122 + 443 + 43 + 0 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 57902589 + ... + 60172568.
It is an arithmetic number, because the mean of its divisors is an integer number (7259673976893).
Almost surely, 2134014122443430 is an apocalyptic number.
134014122443430 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134014122443430 is an abundant number, since it is smaller than the sum of its proper divisors (214450228447434).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134014122443430 is a wasteful number, since it uses less digits than its factorization.
134014122443430 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118087781 (or 118087778 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 36.
Adding to 134014122443430 its reverse (34344221410431), we get a palindrome (168358343853861).
The spelling of 134014122443430 in words is "one hundred thirty-four trillion, fourteen billion, one hundred twenty-two million, four hundred forty-three thousand, four hundred thirty".
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