13402000211231 has 4 divisors (see below), whose sum is σ = 13713674634792. Its totient is φ = 13090325787672.

The previous prime is 13402000211203. The next prime is 13402000211263. The reversal of 13402000211231 is 13211200020431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13402000211231 - 2³⁰ = 13400926469407 is a prime.

It is a super-2 number, since 2×13402000211231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402000214231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155837211716 + ... + 155837211801.

It is an arithmetic number, because the mean of its divisors is an integer number (3428418658698).

Almost surely, 2^{13402000211231} is an apocalyptic number.

13402000211231 is a deficient number, since it is larger than the sum of its proper divisors (311674423561).

13402000211231 is an equidigital number, since it uses as much as digits as its factorization.

13402000211231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 311674423560.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13402000211231 its reverse (13211200020431), we get a palindrome (26613200231662).

The spelling of 13402000211231 in words is "thirteen trillion, four hundred two billion, two hundred eleven thousand, two hundred thirty-one".