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13402001431 = 713147274741
BaseRepresentation
bin11000111101101001…
…00101000000010111
31021121000020012202101
430132310211000113
5204421403021211
610053511222531
7653054063320
oct143664450027
937530205671
1013402001431
115758098045
122720377a47
131357764280
14911cd1447
155368ad5c1
hex31ed25017

13402001431 has 8 divisors (see below), whose sum is σ = 16494771104. Its totient is φ = 10603781280.

The previous prime is 13402001423. The next prime is 13402001489. The reversal of 13402001431 is 13410020431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13402001431 - 23 = 13402001423 is a prime.

It is a super-2 number, since 2×134020014312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13402001399 and 13402001408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402004431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73637280 + ... + 73637461.

It is an arithmetic number, because the mean of its divisors is an integer number (2061846388).

Almost surely, 213402001431 is an apocalyptic number.

13402001431 is a deficient number, since it is larger than the sum of its proper divisors (3092769673).

13402001431 is a wasteful number, since it uses less digits than its factorization.

13402001431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 147274761.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 13402001431 its reverse (13410020431), we get a palindrome (26812021862).

The spelling of 13402001431 in words is "thirteen billion, four hundred two million, one thousand, four hundred thirty-one".

Divisors: 1 7 13 91 147274741 1030923187 1914571633 13402001431