Base | Representation |
---|---|
bin | 1100001100000110011001… |
… | …0010111011101000100000 |
3 | 1202110012221102010222112012 |
4 | 3003001212102323220200 |
5 | 3224034311113434100 |
6 | 44300444512052052 |
7 | 2552156256055535 |
oct | 303014622735040 |
9 | 52405842128465 |
10 | 13402014202400 |
11 | 42a784269a17a |
12 | 1605497534028 |
13 | 762a5c6a43a5 |
14 | 3449378dcd8c |
15 | 18393cceb135 |
hex | c30664bba20 |
13402014202400 has 36 divisors (see below), whose sum is σ = 32717667173562. Its totient is φ = 5360805680640.
The previous prime is 13402014202391. The next prime is 13402014202439. The reversal of 13402014202400 is 420241020431.
It can be written as a sum of positive squares in 3 ways, for example, as 12862006740496 + 540007461904 = 3586364^2 + 734852^2 .
It is a super-2 number, since 2×134020142024002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 8376258077 + ... + 8376259676.
Almost surely, 213402014202400 is an apocalyptic number.
13402014202400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13402014202400 is an abundant number, since it is smaller than the sum of its proper divisors (19315652971162).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13402014202400 is a wasteful number, since it uses less digits than its factorization.
13402014202400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16752517773 (or 16752517760 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 13402014202400 its reverse (420241020431), we get a palindrome (13822255222831).
The spelling of 13402014202400 in words is "thirteen trillion, four hundred two billion, fourteen million, two hundred two thousand, four hundred".
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