Base | Representation |
---|---|
bin | 11000111101101010… |
… | …00000000000011111 |
3 | 1021121000102211110200 |
4 | 30132311000000133 |
5 | 204421420041111 |
6 | 10053513434543 |
7 | 653055033630 |
oct | 143665000037 |
9 | 37530384420 |
10 | 13402112031 |
11 | 5758163150 |
12 | 272040ba53 |
13 | 13577a2709 |
14 | 911d1d887 |
15 | 5368d1256 |
hex | 31ed4001f |
13402112031 has 48 divisors (see below), whose sum is σ = 24190932480. Its totient is φ = 6946119360.
The previous prime is 13402111969. The next prime is 13402112071. The reversal of 13402112031 is 13021120431.
It is not a de Polignac number, because 13402112031 - 29 = 13402111519 is a prime.
It is a super-2 number, since 2×134021120312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13402111995 and 13402112013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13402112071) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 282201 + ... + 326253.
It is an arithmetic number, because the mean of its divisors is an integer number (503977760).
Almost surely, 213402112031 is an apocalyptic number.
13402112031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13402112031 is a deficient number, since it is larger than the sum of its proper divisors (10788820449).
13402112031 is a wasteful number, since it uses less digits than its factorization.
13402112031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44516 (or 44513 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 13402112031 its reverse (13021120431), we get a palindrome (26423232462).
The spelling of 13402112031 in words is "thirteen billion, four hundred two million, one hundred twelve thousand, thirty-one".
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