13402112043151 has 8 divisors (see below), whose sum is σ = 14521590021680. Its totient is φ = 12295283533632.

The previous prime is 13402112043127. The next prime is 13402112043157. The reversal of 13402112043151 is 15134021120431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13402112043151 - 2¹¹ = 13402112041103 is a prime.

It is a super-3 number, since 3×13402112043151³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402112043157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3162365046 + ... + 3162369283.

It is an arithmetic number, because the mean of its divisors is an integer number (1815198752710).

Almost surely, 2^{13402112043151} is an apocalyptic number.

13402112043151 is a deficient number, since it is larger than the sum of its proper divisors (1119477978529).

13402112043151 is a wasteful number, since it uses less digits than its factorization.

13402112043151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6324734505.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 13402112043151 its reverse (15134021120431), we get a palindrome (28536133163582).

The spelling of 13402112043151 in words is "thirteen trillion, four hundred two billion, one hundred twelve million, forty-three thousand, one hundred fifty-one".