13403000452335 has 32 divisors (see below), whose sum is σ = 23094617591808. Its totient is φ = 6598338276480.

The previous prime is 13403000452297. The next prime is 13403000452343. The reversal of 13403000452335 is 53325400030431.

It is not a de Polignac number, because 13403000452335 - 2²⁴ = 13402983675119 is a prime.

It is a super-2 number, since 2×13403000452335² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13403000452296 and 13403000452305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25989904 + ... + 26500586.

It is an arithmetic number, because the mean of its divisors is an integer number (721706799744).

Almost surely, 2^{13403000452335} is an apocalyptic number.

13403000452335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13403000452335 is a deficient number, since it is larger than the sum of its proper divisors (9691617139473).

13403000452335 is a wasteful number, since it uses less digits than its factorization.

13403000452335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 645295.

The product of its (nonzero) digits is 64800, while the sum is 33.

Adding to 13403000452335 its reverse (53325400030431), we get a palindrome (66728400482766).

The spelling of 13403000452335 in words is "thirteen trillion, four hundred three billion, four hundred fifty-two thousand, three hundred thirty-five".