Base | Representation |
---|---|
bin | 11000111101110011… |
… | …01001101011100100 |
3 | 1021121002201202222210 |
4 | 30132321221223210 |
5 | 204422223100200 |
6 | 10053555523420 |
7 | 653101302432 |
oct | 143671515344 |
9 | 37532652883 |
10 | 13403331300 |
11 | 5758916207 |
12 | 27208b9570 |
13 | 1357b0b688 |
14 | 912159d52 |
15 | 536a72650 |
hex | 31ee69ae4 |
13403331300 has 36 divisors (see below), whose sum is σ = 38780306096. Its totient is φ = 3574221600.
The previous prime is 13403331247. The next prime is 13403331311. The reversal of 13403331300 is 313330431.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 22338586 + ... + 22339185.
Almost surely, 213403331300 is an apocalyptic number.
13403331300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13403331300 is an abundant number, since it is smaller than the sum of its proper divisors (25376974796).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13403331300 is a wasteful number, since it uses less digits than its factorization.
13403331300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44677788 (or 44677781 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 13403331300 its reverse (313330431), we get a palindrome (13716661731).
The spelling of 13403331300 in words is "thirteen billion, four hundred three million, three hundred thirty-one thousand, three hundred".
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