1340350415511 has 4 divisors (see below), whose sum is σ = 1787133887352. Its totient is φ = 893566943672.

The previous prime is 1340350415497. The next prime is 1340350415519. The reversal of 1340350415511 is 1155140530431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340350415511 - 2²⁷ = 1340216197783 is a prime.

It is a super-2 number, since 2×1340350415511² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340350415519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223391735916 + ... + 223391735921.

It is an arithmetic number, because the mean of its divisors is an integer number (446783471838).

Almost surely, 2^{1340350415511} is an apocalyptic number.

1340350415511 is a deficient number, since it is larger than the sum of its proper divisors (446783471841).

1340350415511 is an equidigital number, since it uses as much as digits as its factorization.

1340350415511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 446783471840.

The product of its (nonzero) digits is 18000, while the sum is 33.

Adding to 1340350415511 its reverse (1155140530431), we get a palindrome (2495490945942).

The spelling of 1340350415511 in words is "one trillion, three hundred forty billion, three hundred fifty million, four hundred fifteen thousand, five hundred eleven".