Base | Representation |
---|---|
bin | 11110011110011110001110… |
… | …011011101010111000110100 |
3 | 122120120122212212001221022202 |
4 | 132132132032123222320310 |
5 | 120032014032102241000 |
6 | 1153023010042044032 |
7 | 40142512002022511 |
oct | 3636361633527064 |
9 | 576518785057282 |
10 | 134035434024500 |
11 | 39787121234968 |
12 | 13048b6b7a9618 |
13 | 59a3644499908 |
14 | 25154c7508308 |
15 | 1076881268dd5 |
hex | 79e78e6eae34 |
134035434024500 has 48 divisors (see below), whose sum is σ = 292734541811712. Its totient is φ = 53613962272800.
The previous prime is 134035434024497. The next prime is 134035434024517. The reversal of 134035434024500 is 5420434530431.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 211234709 + ... + 211868291.
It is an arithmetic number, because the mean of its divisors is an integer number (6098636287744).
Almost surely, 2134035434024500 is an apocalyptic number.
134035434024500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134035434024500 is an abundant number, since it is smaller than the sum of its proper divisors (158699107787212).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134035434024500 is a wasteful number, since it uses less digits than its factorization.
134035434024500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1056705 (or 1056693 counting only the distinct ones).
The product of its (nonzero) digits is 345600, while the sum is 38.
Adding to 134035434024500 its reverse (5420434530431), we get a palindrome (139455868554931).
The spelling of 134035434024500 in words is "one hundred thirty-four trillion, thirty-five billion, four hundred thirty-four million, twenty-four thousand, five hundred".
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