Base | Representation |
---|---|
bin | 1100001100001110010010… |
… | …1011000011011111010111 |
3 | 1202110102102011202222122201 |
4 | 3003003210223003133113 |
5 | 3224103131410032010 |
6 | 44301435132305331 |
7 | 2552262642653665 |
oct | 303034453033727 |
9 | 52412364688581 |
10 | 13404134455255 |
11 | 42a8730500565 |
12 | 1605989612247 |
13 | 763009a3378b |
14 | 344a9933bc35 |
15 | 183a1401423a |
hex | c30e4ac37d7 |
13404134455255 has 16 divisors (see below), whose sum is σ = 16122351144960. Its totient is φ = 10698409975968.
The previous prime is 13404134455207. The next prime is 13404134455267. The reversal of 13404134455255 is 55255443140431.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 13404134455255 - 217 = 13404134324183 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1898434 + ... + 5514736.
It is an arithmetic number, because the mean of its divisors is an integer number (1007646946560).
Almost surely, 213404134455255 is an apocalyptic number.
13404134455255 is a deficient number, since it is larger than the sum of its proper divisors (2718216689705).
13404134455255 is an equidigital number, since it uses as much as digits as its factorization.
13404134455255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3618030.
The product of its (nonzero) digits is 2880000, while the sum is 46.
Adding to 13404134455255 its reverse (55255443140431), we get a palindrome (68659577595686).
The spelling of 13404134455255 in words is "thirteen trillion, four hundred four billion, one hundred thirty-four million, four hundred fifty-five thousand, two hundred fifty-five".
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