13404143432140 has 48 divisors (see below), whose sum is σ = 30212788136832. Its totient is φ = 4977138825216.

The previous prime is 13404143432101. The next prime is 13404143432161. The reversal of 13404143432140 is 4123434140431.

It is a super-3 number, since 3×13404143432140³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (34).

It is a junction number, because it is equal to n+sod(n) for n = 13404143432096 and 13404143432105.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 270002244 + ... + 270051883.

It is an arithmetic number, because the mean of its divisors is an integer number (629433086184).

Almost surely, 2^{13404143432140} is an apocalyptic number.

13404143432140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13404143432140 is an abundant number, since it is smaller than the sum of its proper divisors (16808644704692).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13404143432140 is a wasteful number, since it uses less digits than its factorization.

13404143432140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 540054226 (or 540054224 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 13404143432140 its reverse (4123434140431), we get a palindrome (17527577572571).

The spelling of 13404143432140 in words is "thirteen trillion, four hundred four billion, one hundred forty-three million, four hundred thirty-two thousand, one hundred forty".