Base | Representation |
---|---|
bin | 11110011110100100011101… |
… | …100111100010000011000000 |
3 | 122120121022011121001220020210 |
4 | 132132210131213202003000 |
5 | 120032121241044240300 |
6 | 1153030034402434120 |
7 | 40143136653316455 |
oct | 3636443547420300 |
9 | 576538147056223 |
10 | 134042131243200 |
11 | 39789a48685454 |
12 | 1304a31a662940 |
13 | 59a4170b3cb0b |
14 | 2515960b6982c |
15 | 1076b241c5050 |
hex | 79e91d9e20c0 |
134042131243200 has 336 divisors, whose sum is σ = 490146015611520. Its totient is φ = 31871317524480.
The previous prime is 134042131243171. The next prime is 134042131243253. The reversal of 134042131243200 is 2342131240431.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 41677842 + ... + 44778641.
Almost surely, 2134042131243200 is an apocalyptic number.
134042131243200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134042131243200 is an abundant number, since it is smaller than the sum of its proper divisors (356103884368320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134042131243200 is a wasteful number, since it uses less digits than its factorization.
134042131243200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86456544 (or 86456529 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 134042131243200 its reverse (2342131240431), we get a palindrome (136384262483631).
The spelling of 134042131243200 in words is "one hundred thirty-four trillion, forty-two billion, one hundred thirty-one million, two hundred forty-three thousand, two hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •