13404310401132 has 72 divisors (see below), whose sum is σ = 38736840638496. Its totient is φ = 3828489836544.

The previous prime is 13404310401113. The next prime is 13404310401149. The reversal of 13404310401132 is 23110401340431.

13404310401132 is a `hidden beast` number, since 1 + 340 + 4 + 310 + 4 + 0 + 1 + 1 + 3 + 2 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 13404310401096 and 13404310401105.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8382453 + ... + 9852620.

Almost surely, 2^{13404310401132} is an apocalyptic number.

13404310401132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13404310401132 is an abundant number, since it is smaller than the sum of its proper divisors (25332530237364).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13404310401132 is a wasteful number, since it uses less digits than its factorization.

13404310401132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18238007 (or 18238002 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 13404310401132 its reverse (23110401340431), we get a palindrome (36514711741563).

The spelling of 13404310401132 in words is "thirteen trillion, four hundred four billion, three hundred ten million, four hundred one thousand, one hundred thirty-two".