Base | Representation |
---|---|
bin | 11000111101111010… |
… | …11110011111010000 |
3 | 1021121011121201111000 |
4 | 30132331132133100 |
5 | 204423002142112 |
6 | 10054033222000 |
7 | 653112650025 |
oct | 143675363720 |
9 | 37534551430 |
10 | 13404334032 |
11 | 5759440611 |
12 | 2721101900 |
13 | 135809cbcb |
14 | 91233b54c |
15 | 536bbe7dc |
hex | 31ef5e7d0 |
13404334032 has 80 divisors (see below), whose sum is σ = 39716584960. Its totient is φ = 4323974400.
The previous prime is 13404334019. The next prime is 13404334037. The reversal of 13404334032 is 23043340431.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 13404333987 and 13404334005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13404334037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 487069 + ... + 513852.
It is an arithmetic number, because the mean of its divisors is an integer number (496457312).
Almost surely, 213404334032 is an apocalyptic number.
13404334032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13404334032 is an abundant number, since it is smaller than the sum of its proper divisors (26312250928).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13404334032 is a wasteful number, since it uses less digits than its factorization.
13404334032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1000969 (or 1000957 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 27.
Adding to 13404334032 its reverse (23043340431), we get a palindrome (36447674463).
The spelling of 13404334032 in words is "thirteen billion, four hundred four million, three hundred thirty-four thousand, thirty-two".
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