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13404431364 = 2231117035947
BaseRepresentation
bin11000111101111011…
…10110010000000100
31021121011210122222220
430132331312100010
5204423013300424
610054035252340
7653113533552
oct143675662004
937534718886
1013404431364
1157594a7755
12272114a0b0
1313581052bc
14912364bd2
15536bdd579
hex31ef76404

13404431364 has 12 divisors (see below), whose sum is σ = 31277006544. Its totient is φ = 4468143784.

The previous prime is 13404431357. The next prime is 13404431389. The reversal of 13404431364 is 46313440431.

It is a happy number.

13404431364 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (12).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 558517962 + ... + 558517985.

It is an arithmetic number, because the mean of its divisors is an integer number (2606417212).

Almost surely, 213404431364 is an apocalyptic number.

It is an amenable number.

13404431364 is an abundant number, since it is smaller than the sum of its proper divisors (17872575180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13404431364 is a wasteful number, since it uses less digits than its factorization.

13404431364 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1117035954 (or 1117035952 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 13404431364 its reverse (46313440431), we get a palindrome (59717871795).

The spelling of 13404431364 in words is "thirteen billion, four hundred four million, four hundred thirty-one thousand, three hundred sixty-four".

Divisors: 1 2 3 4 6 12 1117035947 2234071894 3351107841 4468143788 6702215682 13404431364