Search a number
-
+
1340477674693 is a prime number
BaseRepresentation
bin10011100000011010101…
…100100001010011000101
311202011000012020101012221
4103200122230201103011
5133430244241042233
62503450144412341
7165563200143643
oct23403254412305
94664005211187
101340477674693
11477547779303
121979633170b1
1399539116141
1448c4537a193
1524d0781542d
hex1381ab214c5

1340477674693 has 2 divisors, whose sum is σ = 1340477674694. Its totient is φ = 1340477674692.

The previous prime is 1340477674663. The next prime is 1340477674709. The reversal of 1340477674693 is 3964767740431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1156091597089 + 184386077604 = 1075217^2 + 429402^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340477674693 - 213 = 1340477666501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340477674603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670238837346 + 670238837347.

It is an arithmetic number, because the mean of its divisors is an integer number (670238837347).

Almost surely, 21340477674693 is an apocalyptic number.

It is an amenable number.

1340477674693 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340477674693 is an equidigital number, since it uses as much as digits as its factorization.

1340477674693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64012032, while the sum is 61.

The spelling of 1340477674693 in words is "one trillion, three hundred forty billion, four hundred seventy-seven million, six hundred seventy-four thousand, six hundred ninety-three".