13405541245031 has 4 divisors (see below), whose sum is σ = 14436736725432. Its totient is φ = 12374345764632.

The previous prime is 13405541245009. The next prime is 13405541245111. The reversal of 13405541245031 is 13054214550431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13405541245031 - 2²² = 13405537050727 is a prime.

It is a super-2 number, since 2×13405541245031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13405541245531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 515597740181 + ... + 515597740206.

It is an arithmetic number, because the mean of its divisors is an integer number (3609184181358).

Almost surely, 2^{13405541245031} is an apocalyptic number.

13405541245031 is a deficient number, since it is larger than the sum of its proper divisors (1031195480401).

13405541245031 is a wasteful number, since it uses less digits than its factorization.

13405541245031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1031195480400.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 13405541245031 its reverse (13054214550431), we get a palindrome (26459755795462).

The spelling of 13405541245031 in words is "thirteen trillion, four hundred five billion, five hundred forty-one million, two hundred forty-five thousand, thirty-one".