Base | Representation |
---|---|
bin | 11110011111000000110001… |
… | …100101110011011100010000 |
3 | 122120201012122012202220122122 |
4 | 132133000301211303130100 |
5 | 120033121020430334202 |
6 | 1153052023121153412 |
7 | 40145264210014664 |
oct | 3637006145633420 |
9 | 576635565686578 |
10 | 134072531105552 |
11 | 397a09285aaa36 |
12 | 130541a348b868 |
13 | 59a6ca6cc8950 |
14 | 25172063408a4 |
15 | 1077802e869a2 |
hex | 79f031973710 |
134072531105552 has 40 divisors (see below), whose sum is σ = 286253248452864. Its totient is φ = 60440568580224.
The previous prime is 134072531105519. The next prime is 134072531105587. The reversal of 134072531105552 is 255501135270431.
It is a super-3 number, since 3×1340725311055523 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7495101248 + ... + 7495119135.
Almost surely, 2134072531105552 is an apocalyptic number.
It is an amenable number.
134072531105552 is an abundant number, since it is smaller than the sum of its proper divisors (152180717347312).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134072531105552 is a wasteful number, since it uses less digits than its factorization.
134072531105552 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14990220447 (or 14990220441 counting only the distinct ones).
The product of its (nonzero) digits is 630000, while the sum is 44.
Adding to 134072531105552 its reverse (255501135270431), we get a palindrome (389573666375983).
The spelling of 134072531105552 in words is "one hundred thirty-four trillion, seventy-two billion, five hundred thirty-one million, one hundred five thousand, five hundred fifty-two".
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