Base | Representation |
---|---|
bin | 10011100001000010010… |
… | …110111011111010010011 |
3 | 11202012201120100202020012 |
4 | 103201002112323322103 |
5 | 133433130113331141 |
6 | 2504040155105135 |
7 | 165615530205332 |
oct | 23410226737223 |
9 | 4665646322205 |
10 | 1341143105171 |
11 | 477859357051 |
12 | 197b0a1421ab |
13 | 99613c4069c |
14 | 48ca98b5d19 |
15 | 24d45e59ceb |
hex | 138425bbe93 |
1341143105171 has 2 divisors, whose sum is σ = 1341143105172. Its totient is φ = 1341143105170.
The previous prime is 1341143105149. The next prime is 1341143105243. The reversal of 1341143105171 is 1715013411431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1341143105171 - 238 = 1066265198227 is a prime.
It is not a weakly prime, because it can be changed into another prime (1341143105131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670571552585 + 670571552586.
It is an arithmetic number, because the mean of its divisors is an integer number (670571552586).
Almost surely, 21341143105171 is an apocalyptic number.
1341143105171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341143105171 is an equidigital number, since it uses as much as digits as its factorization.
1341143105171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5040, while the sum is 32.
The spelling of 1341143105171 in words is "one trillion, three hundred forty-one billion, one hundred forty-three million, one hundred five thousand, one hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •