1341143105131 has 2 divisors, whose sum is σ = 1341143105132. Its totient is φ = 1341143105130.

The previous prime is 1341143105129. The next prime is 1341143105149. The reversal of 1341143105131 is 1315013411431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1341143105131 - 2¹ = 1341143105129 is a prime.

It is a super-2 number, since 2×1341143105131² (a number of 25 digits) contains 22 as substring.

Together with 1341143105129, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1341143105131.

It is not a weakly prime, because it can be changed into another prime (1341143105171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670571552565 + 670571552566.

It is an arithmetic number, because the mean of its divisors is an integer number (670571552566).

Almost surely, 2^{1341143105131} is an apocalyptic number.

1341143105131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341143105131 is an equidigital number, since it uses as much as digits as its factorization.

1341143105131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 1341143105131 its reverse (1315013411431), we get a palindrome (2656156516562).

The spelling of 1341143105131 in words is "one trillion, three hundred forty-one billion, one hundred forty-three million, one hundred five thousand, one hundred thirty-one".