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1341143105149 is a prime number
BaseRepresentation
bin10011100001000010010…
…110111011111001111101
311202012201120100202012101
4103201002112323321331
5133433130113331044
62504040155105101
7165615530205301
oct23410226737175
94665646322171
101341143105149
11477859357031
12197b0a142191
1399613c40683
1448ca98b5d01
1524d45e59cd4
hex138425bbe7d

1341143105149 has 2 divisors, whose sum is σ = 1341143105150. Its totient is φ = 1341143105148.

The previous prime is 1341143105131. The next prime is 1341143105171. The reversal of 1341143105149 is 9415013411431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 903104301124 + 438038804025 = 950318^2 + 661845^2 .

It is a cyclic number.

It is not a de Polignac number, because 1341143105149 - 211 = 1341143103101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1341143105129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670571552574 + 670571552575.

It is an arithmetic number, because the mean of its divisors is an integer number (670571552575).

Almost surely, 21341143105149 is an apocalyptic number.

It is an amenable number.

1341143105149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341143105149 is an equidigital number, since it uses as much as digits as its factorization.

1341143105149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 37.

The spelling of 1341143105149 in words is "one trillion, three hundred forty-one billion, one hundred forty-three million, one hundred five thousand, one hundred forty-nine".