Base | Representation |
---|---|
bin | 1100001100101001101111… |
… | …1000101011010011101000 |
3 | 1202111010102201102020010010 |
4 | 3003022123320223103220 |
5 | 3224213224311132130 |
6 | 44305054242451520 |
7 | 2552643360320625 |
oct | 303123370532350 |
9 | 52433381366103 |
10 | 13411503224040 |
11 | 4300871a29619 |
12 | 16072a5363ba0 |
13 | 7639125647ac |
14 | 345197c4d34c |
15 | 183ce5dc30b0 |
hex | c329be2b4e8 |
13411503224040 has 128 divisors (see below), whose sum is σ = 40281666768000. Its totient is φ = 3572211253248.
The previous prime is 13411503224039. The next prime is 13411503224047. The reversal of 13411503224040 is 4042230511431.
13411503224040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 13411503223989 and 13411503224007.
It is not an unprimeable number, because it can be changed into a prime (13411503224047) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 462786271 + ... + 462815249.
It is an arithmetic number, because the mean of its divisors is an integer number (314700521625).
Almost surely, 213411503224040 is an apocalyptic number.
13411503224040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13411503224040 is an abundant number, since it is smaller than the sum of its proper divisors (26870163543960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13411503224040 is a wasteful number, since it uses less digits than its factorization.
13411503224040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33379 (or 33375 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 13411503224040 its reverse (4042230511431), we get a palindrome (17453733735471).
The spelling of 13411503224040 in words is "thirteen trillion, four hundred eleven billion, five hundred three million, two hundred twenty-four thousand, forty".
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