Base | Representation |
---|---|
bin | 10011100001000010111… |
… | …010111011111100111000 |
3 | 11202012202020010012211122 |
4 | 103201002322323330320 |
5 | 133433140022330040 |
6 | 2504041133244412 |
7 | 165616003342430 |
oct | 23410272737470 |
9 | 4665666105748 |
10 | 1341152542520 |
11 | 47786371250a |
12 | 197b11333708 |
13 | 99615b9610b |
14 | 48caac512c0 |
15 | 24d46bc11b5 |
hex | 13842ebbf38 |
1341152542520 has 64 divisors (see below), whose sum is σ = 3453802787520. Its totient is φ = 459140419584.
The previous prime is 1341152542489. The next prime is 1341152542547. The reversal of 1341152542520 is 252452511431.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3370127 + ... + 3747006.
It is an arithmetic number, because the mean of its divisors is an integer number (53965668555).
Almost surely, 21341152542520 is an apocalyptic number.
1341152542520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1341152542520 is an abundant number, since it is smaller than the sum of its proper divisors (2112650245000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1341152542520 is a wasteful number, since it uses less digits than its factorization.
1341152542520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7117824 (or 7117820 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 35.
The spelling of 1341152542520 in words is "one trillion, three hundred forty-one billion, one hundred fifty-two million, five hundred forty-two thousand, five hundred twenty".
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