13413004332101 has 8 divisors (see below), whose sum is σ = 14671597236384. Its totient is φ = 12160949573520.

The previous prime is 13413004332071. The next prime is 13413004332107. The reversal of 13413004332101 is 10123340031431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-13413004332101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13413004332107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1634532131 + ... + 1634540336.

It is an arithmetic number, because the mean of its divisors is an integer number (1833949654548).

Almost surely, 2^{13413004332101} is an apocalyptic number.

13413004332101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13413004332101 is a deficient number, since it is larger than the sum of its proper divisors (1258592904283).

13413004332101 is a wasteful number, since it uses less digits than its factorization.

13413004332101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3269072851.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 13413004332101 its reverse (10123340031431), we get a palindrome (23536344363532).

The spelling of 13413004332101 in words is "thirteen trillion, four hundred thirteen billion, four million, three hundred thirty-two thousand, one hundred one".