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134131031405 = 575965964237
BaseRepresentation
bin111110011101011010…
…1010001110101101101
3110211012211012101100222
41330322311101311231
54144200021001110
6141341405301125
712455614645460
oct1747265216555
9424184171328
10134131031405
115198051a178
1221bb42647a5
13c8579b3307
1466c5dab2d7
15375086cc55
hex1f3ad51d6d

134131031405 has 16 divisors (see below), whose sum is σ = 183957075840. Its totient is φ = 91972590912.

The previous prime is 134131031371. The next prime is 134131031417. The reversal of 134131031405 is 504130131431.

It is a cyclic number.

It is not a de Polignac number, because 134131031405 - 218 = 134130769261 is a prime.

It is a super-2 number, since 2×1341310314052 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2055947 + ... + 2120183.

It is an arithmetic number, because the mean of its divisors is an integer number (11497317240).

Almost surely, 2134131031405 is an apocalyptic number.

It is an amenable number.

134131031405 is a deficient number, since it is larger than the sum of its proper divisors (49826044435).

134131031405 is an equidigital number, since it uses as much as digits as its factorization.

134131031405 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123908.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 134131031405 its reverse (504130131431), we get a palindrome (638261162836).

The spelling of 134131031405 in words is "one hundred thirty-four billion, one hundred thirty-one million, thirty-one thousand, four hundred five".

Divisors: 1 5 7 35 59659 64237 298295 321185 417613 449659 2088065 2248295 3832315183 19161575915 26826206281 134131031405