Base | Representation |
---|---|
bin | 1100001100110000110111… |
… | …0010001011111011000111 |
3 | 1202111022100220010001210012 |
4 | 3003030031302023323013 |
5 | 3224231133004002010 |
6 | 44310012024020435 |
7 | 2553041622602324 |
oct | 303141562137307 |
9 | 52438326101705 |
10 | 13413414125255 |
11 | 430166264aa21 |
12 | 160773930171b |
13 | 763b58414181 |
14 | 3452d9953b4b |
15 | 183da8a36005 |
hex | c330dc8bec7 |
13413414125255 has 4 divisors (see below), whose sum is σ = 16096096950312. Its totient is φ = 10730731300200.
The previous prime is 13413414125249. The next prime is 13413414125351. The reversal of 13413414125255 is 55252141431431.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-13413414125255 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1341341412521 + ... + 1341341412530.
It is an arithmetic number, because the mean of its divisors is an integer number (4024024237578).
Almost surely, 213413414125255 is an apocalyptic number.
13413414125255 is a deficient number, since it is larger than the sum of its proper divisors (2682682825057).
13413414125255 is an equidigital number, since it uses as much as digits as its factorization.
13413414125255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2682682825056.
The product of its digits is 288000, while the sum is 41.
Adding to 13413414125255 its reverse (55252141431431), we get a palindrome (68665555556686).
The spelling of 13413414125255 in words is "thirteen trillion, four hundred thirteen billion, four hundred fourteen million, one hundred twenty-five thousand, two hundred fifty-five".
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