1341410251230 has 288 divisors, whose sum is σ = 4111931865600. Its totient is φ = 297124571520.

The previous prime is 1341410251219. The next prime is 1341410251253. The reversal of 1341410251230 is 321520141431.

1341410251230 is a `hidden beast` number, since 1 + 3 + 4 + 14 + 102 + 512 + 30 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 1341410251194 and 1341410251203.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 187370391 + ... + 187377549.

It is an arithmetic number, because the mean of its divisors is an integer number (14277541200).

Almost surely, 2^{1341410251230} is an apocalyptic number.

1341410251230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1341410251230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2055965932800).

1341410251230 is an abundant number, since it is smaller than the sum of its proper divisors (2770521614370).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1341410251230 is a wasteful number, since it uses less digits than its factorization.

1341410251230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7380 (or 7306 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 1341410251230 its reverse (321520141431), we get a palindrome (1662930392661).

The spelling of 1341410251230 in words is "one trillion, three hundred forty-one billion, four hundred ten million, two hundred fifty-one thousand, two hundred thirty".