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13414104311 is a prime number
BaseRepresentation
bin11000111111000101…
…01111110011110111
31021121212000002210012
430133202233303313
5204433002314221
610055022450435
7653262001556
oct143742576367
937555002705
1013414104311
115763a04123
122724433a1b
13135a11103a
14913761d9d
1553799e65b
hex31f8afcf7

13414104311 has 2 divisors, whose sum is σ = 13414104312. Its totient is φ = 13414104310.

The previous prime is 13414104307. The next prime is 13414104313. The reversal of 13414104311 is 11340141431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13414104311 - 22 = 13414104307 is a prime.

Together with 13414104313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13414104313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707052155 + 6707052156.

It is an arithmetic number, because the mean of its divisors is an integer number (6707052156).

Almost surely, 213414104311 is an apocalyptic number.

13414104311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13414104311 is an equidigital number, since it uses as much as digits as its factorization.

13414104311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13414104311 its reverse (11340141431), we get a palindrome (24754245742).

The spelling of 13414104311 in words is "thirteen billion, four hundred fourteen million, one hundred four thousand, three hundred eleven".