1341424150113 has 4 divisors (see below), whose sum is σ = 1788565533488. Its totient is φ = 894282766740.

The previous prime is 1341424150109. The next prime is 1341424150153. The reversal of 1341424150113 is 3110514241431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1341424150113 - 2² = 1341424150109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341424150153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223570691683 + ... + 223570691688.

It is an arithmetic number, because the mean of its divisors is an integer number (447141383372).

Almost surely, 2^{1341424150113} is an apocalyptic number.

It is an amenable number.

1341424150113 is a deficient number, since it is larger than the sum of its proper divisors (447141383375).

1341424150113 is an equidigital number, since it uses as much as digits as its factorization.

1341424150113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447141383374.

The product of its (nonzero) digits is 5760, while the sum is 30.

Adding to 1341424150113 its reverse (3110514241431), we get a palindrome (4451938391544).

The spelling of 1341424150113 in words is "one trillion, three hundred forty-one billion, four hundred twenty-four million, one hundred fifty thousand, one hundred thirteen".