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13414310293 is a prime number
BaseRepresentation
bin11000111111000111…
…00010000110010101
31021121212101120100011
430133203202012111
5204433030412133
610055031120221
7653263520236
oct143743420625
937555346304
1013414310293
11576403495a
122724513071
13135a183a17
149137b708d
155379e06cd
hex31f8e2195

13414310293 has 2 divisors, whose sum is σ = 13414310294. Its totient is φ = 13414310292.

The previous prime is 13414310291. The next prime is 13414310317. The reversal of 13414310293 is 39201341431.

13414310293 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9845203729 + 3569106564 = 99223^2 + 59742^2 .

It is a cyclic number.

It is not a de Polignac number, because 13414310293 - 21 = 13414310291 is a prime.

Together with 13414310291, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13414310291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707155146 + 6707155147.

It is an arithmetic number, because the mean of its divisors is an integer number (6707155147).

Almost surely, 213414310293 is an apocalyptic number.

It is an amenable number.

13414310293 is a deficient number, since it is larger than the sum of its proper divisors (1).

13414310293 is an equidigital number, since it uses as much as digits as its factorization.

13414310293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 31.

The spelling of 13414310293 in words is "thirteen billion, four hundred fourteen million, three hundred ten thousand, two hundred ninety-three".