13421413223041 has 4 divisors (see below), whose sum is σ = 14210908118532. Its totient is φ = 12631918327552.

The previous prime is 13421413223011. The next prime is 13421413223081. The reversal of 13421413223041 is 14032231412431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7845203263041 + 5576209960000 = 2800929^2 + 2361400^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13421413223041 is a prime.

It is a super-2 number, since 2×13421413223041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13421413222994 and 13421413223012.

It is not an unprimeable number, because it can be changed into a prime (13421413223011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 394747447720 + ... + 394747447753.

It is an arithmetic number, because the mean of its divisors is an integer number (3552727029633).

Almost surely, 2^{13421413223041} is an apocalyptic number.

It is an amenable number.

13421413223041 is a deficient number, since it is larger than the sum of its proper divisors (789494895491).

13421413223041 is an equidigital number, since it uses as much as digits as its factorization.

13421413223041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 789494895490.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13421413223041 its reverse (14032231412431), we get a palindrome (27453644635472).

The spelling of 13421413223041 in words is "thirteen trillion, four hundred twenty-one billion, four hundred thirteen million, two hundred twenty-three thousand, forty-one".