Base | Representation |
---|---|
bin | 10011100010011001010… |
… | …001111101110110101111 |
3 | 11202100111012102211101012 |
4 | 103202121101331312233 |
5 | 133444121430421312 |
6 | 2504441011535435 |
7 | 165666625526555 |
oct | 23423121756657 |
9 | 4670435384335 |
10 | 1342601420207 |
11 | 478437555793 |
12 | 1982565ba57b |
13 | 997b70c91a8 |
14 | 48da7447bd5 |
15 | 24dcdebd322 |
hex | 1389947ddaf |
1342601420207 has 2 divisors, whose sum is σ = 1342601420208. Its totient is φ = 1342601420206.
The previous prime is 1342601420201. The next prime is 1342601420231. The reversal of 1342601420207 is 7020241062431.
It is a weak prime.
It is an emirp because it is prime and its reverse (7020241062431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1342601420207 - 26 = 1342601420143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342601420201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671300710103 + 671300710104.
It is an arithmetic number, because the mean of its divisors is an integer number (671300710104).
Almost surely, 21342601420207 is an apocalyptic number.
1342601420207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342601420207 is an equidigital number, since it uses as much as digits as its factorization.
1342601420207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 1342601420207 its reverse (7020241062431), we get a palindrome (8362842482638).
The spelling of 1342601420207 in words is "one trillion, three hundred forty-two billion, six hundred one million, four hundred twenty thousand, two hundred seven".
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