Base | Representation |
---|---|
bin | 10011100010011001010… |
… | …001111101110111000111 |
3 | 11202100111012102211102002 |
4 | 103202121101331313013 |
5 | 133444121430421411 |
6 | 2504441011535515 |
7 | 165666625526621 |
oct | 23423121756707 |
9 | 4670435384362 |
10 | 1342601420231 |
11 | 478437555805 |
12 | 1982565ba59b |
13 | 997b70c91c6 |
14 | 48da7447c11 |
15 | 24dcdebd33b |
hex | 1389947ddc7 |
1342601420231 has 2 divisors, whose sum is σ = 1342601420232. Its totient is φ = 1342601420230.
The previous prime is 1342601420207. The next prime is 1342601420309. The reversal of 1342601420231 is 1320241062431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1342601420231 - 222 = 1342597225927 is a prime.
It is a super-2 number, since 2×13426014202312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1342601420194 and 1342601420203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1342601420201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671300710115 + 671300710116.
It is an arithmetic number, because the mean of its divisors is an integer number (671300710116).
Almost surely, 21342601420231 is an apocalyptic number.
1342601420231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342601420231 is an equidigital number, since it uses as much as digits as its factorization.
1342601420231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1342601420231 its reverse (1320241062431), we get a palindrome (2662842482662).
The spelling of 1342601420231 in words is "one trillion, three hundred forty-two billion, six hundred one million, four hundred twenty thousand, two hundred thirty-one".
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