Base | Representation |
---|---|
bin | 1100001101110010110100… |
… | …1100111100110011110011 |
3 | 1202120000001220220210101001 |
4 | 3003130231030330303303 |
5 | 3230023414000312430 |
6 | 44322101042022431 |
7 | 2554236462462361 |
oct | 303345514746363 |
9 | 52500056823331 |
10 | 13431121104115 |
11 | 4309119795250 |
12 | 160b05b347a17 |
13 | 76571aa1b360 |
14 | 3460d94a6631 |
15 | 18459330d3ca |
hex | c372d33ccf3 |
13431121104115 has 32 divisors (see below), whose sum is σ = 18944633030400. Its totient is φ = 9012139547520.
The previous prime is 13431121104101. The next prime is 13431121104211. The reversal of 13431121104115 is 51140112113431.
It is a happy number.
It is not a de Polignac number, because 13431121104115 - 231 = 13428973620467 is a prime.
It is a super-4 number, since 4×134311211041154 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3331045 + ... + 6161014.
It is an arithmetic number, because the mean of its divisors is an integer number (592019782200).
Almost surely, 213431121104115 is an apocalyptic number.
13431121104115 is a deficient number, since it is larger than the sum of its proper divisors (5513511926285).
13431121104115 is a wasteful number, since it uses less digits than its factorization.
13431121104115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9494067.
The product of its (nonzero) digits is 1440, while the sum is 28.
Adding to 13431121104115 its reverse (51140112113431), we get a palindrome (64571233217546).
The spelling of 13431121104115 in words is "thirteen trillion, four hundred thirty-one billion, one hundred twenty-one million, one hundred four thousand, one hundred fifteen".
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