13431121105501 has 4 divisors (see below), whose sum is σ = 14652132115104. Its totient is φ = 12210110095900.

The previous prime is 13431121105483. The next prime is 13431121105553. The reversal of 13431121105501 is 10550112113431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13431121105501 - 2⁵ = 13431121105469 is a prime.

It is a super-3 number, since 3×13431121105501³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 13431121105501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13431121115501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 610505504785 + ... + 610505504806.

It is an arithmetic number, because the mean of its divisors is an integer number (3663033028776).

Almost surely, 2^{13431121105501} is an apocalyptic number.

13431121105501 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13431121105501 is a deficient number, since it is larger than the sum of its proper divisors (1221011009603).

13431121105501 is a wasteful number, since it uses less digits than its factorization.

13431121105501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1221011009602.

The product of its (nonzero) digits is 1800, while the sum is 28.

Adding to 13431121105501 its reverse (10550112113431), we get a palindrome (23981233218932).

The spelling of 13431121105501 in words is "thirteen trillion, four hundred thirty-one billion, one hundred twenty-one million, one hundred five thousand, five hundred one".