Base | Representation |
---|---|
bin | 10011100010111101101… |
… | …011100110110000011011 |
3 | 11202102001202120122112100 |
4 | 103202331223212300123 |
5 | 134001344300333430 |
6 | 2505021345214443 |
7 | 166021022434644 |
oct | 23427553466033 |
9 | 4672052518470 |
10 | 1343212121115 |
11 | 478720252387 |
12 | 1983a7031423 |
13 | 998837a0687 |
14 | 490245b86cb |
15 | 24e17901960 |
hex | 138bdae6c1b |
1343212121115 has 48 divisors (see below), whose sum is σ = 2429611808832. Its totient is φ = 685190575872.
The previous prime is 1343212121101. The next prime is 1343212121171. The reversal of 1343212121115 is 5111212123431.
1343212121115 is a `hidden beast` number, since 1 + 3 + 432 + 1 + 2 + 1 + 211 + 15 = 666.
It is not a de Polignac number, because 1343212121115 - 210 = 1343212120091 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 23334309 + ... + 23391801.
It is an arithmetic number, because the mean of its divisors is an integer number (50616912684).
Almost surely, 21343212121115 is an apocalyptic number.
1343212121115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1343212121115 is a deficient number, since it is larger than the sum of its proper divisors (1086399687717).
1343212121115 is a wasteful number, since it uses less digits than its factorization.
1343212121115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80100 (or 80097 counting only the distinct ones).
The product of its digits is 1440, while the sum is 27.
Adding to 1343212121115 its reverse (5111212123431), we get a palindrome (6454424244546).
The spelling of 1343212121115 in words is "one trillion, three hundred forty-three billion, two hundred twelve million, one hundred twenty-one thousand, one hundred fifteen".
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