1343411340 has 96 divisors (see below), whose sum is σ = 4043934720. Its totient is φ = 332153856.

The previous prime is 1343411339. The next prime is 1343411369. The reversal of 1343411340 is 431143431.

It is a super-3 number, since 3×1343411340³ (a number of 28 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1343411340.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 41044 + ... + 66116.

It is an arithmetic number, because the mean of its divisors is an integer number (42124320).

Almost surely, 2^1343411340 is an apocalyptic number.

1343411340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1343411340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2021967360).

1343411340 is an abundant number, since it is smaller than the sum of its proper divisors (2700523380).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1343411340 is a wasteful number, since it uses less digits than its factorization.

1343411340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25151 (or 25149 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

The square root of 1343411340 is about 36652.5761713962. The cubic root of 1343411340 is about 1103.4085291365.

Adding to 1343411340 its reverse (431143431), we get a palindrome (1774554771).

The spelling of 1343411340 in words is "one billion, three hundred forty-three million, four hundred eleven thousand, three hundred forty".